# Determine the limiting reactant for 4 mol fe(oh)3 and 6

Write a balanced net ionic equation for the following reaction eqFe(OH)_3(s) + H_2SO_4(aq) o ule0.5in0.3pt/eq.

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## Ionic Equations:

This kind of chemical equation usually contains dissociated ions corresponding to the electrolytes which made up the aqueous solutions. Spectator ions from this equation must be cancelled so that we can have a net ionic equation.

The given incomplete reaction is shown below.

eq m Fe(OH)_3(s) + H_2SO_4(aq) o ule0.5in0.3pt/eq

The products of this reaction are: iron (III) sulphate (which is present in solid form) & water (which is in liquid form).

The complete balanced chemical reaction is shown below.

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eq m 2 Fe(OH)_3(s) + 3H_2SO_4(aq) o Fe_2 (SO_4)_3 (s) + 6H_2O (l)/eq

The ionic equation of this reaction can be shown by writing all the molecules in ionic size as shown below.

eq m 2 Fe(OH)_3(s) + 6H^+ (aq) + 3 SO_4 ^2-(aq) o Fe_2 (SO_4)_3 (s) + 6H_2O (l)/eq

Since, all the ions are present in solid or liquid size except sulfuric acid which is present in aqueous form. There are no spectator ions in this equation. So, the net ionic equation will be identical to the ionic equation shown above. Thus, the net ionic equation will come out as:

eq m 2 Fe(OH)_3(s) + 6H^+ (aq) + 3 SO_4 ^2-(aq) o Fe_2 (SO_4)_3 (s) + 6H_2O (l)/eq

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Precipitation Reactions: Predicting Precipitates and Net Ionic Equations

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Chapter 10/ Lesson 9
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buoidienxanhha.com precipitate reactions. Determine precipitate solubility according khổng lồ solubility rules. Learn to write ionic equations by following a molecular reaction.

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